(7-5)^2+3c=10

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Solution for (7-5)^2+3c=10 equation: 



(7-5)^2+3c=10

We move all terms to the left:

(7-5)^2+3c-(10)=0

determiningTheFunctionDomain
3c-10+(7-5)^2=0

We add all the numbers together, and all the variables

3c-10+2^2=0

We add all the numbers together, and all the variables

3c-6=0

We move all terms containing c to the left, all other terms to the right

3c=6

c=6/3

c=2

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